WebMOV AL,[SI]+1234H Example: let you have DS = 0200H, CS = 0100H, IP = 0000H, AL=BEH, SI = 2000H, and you execute the instruction MOV AL,[SI]+1234H. How these instruction is executed and what are the memory mapping of it? • The starting address of your instruction is: PA = CS*10H+IP = 0100 * 10 + 0000 = 1000H. Web1 Answer. The value of the code segment register (CS) = 3560h The value of the Instruction Pointer, holding address of the instruction = 101Ah Physical address of the instruction Physical Address = CS (Hex) x 16 + IP. The value of the stack segment register (SS) = 2067h The value of the stack pointer (SP) which is Offset = 1235h Thus, Physical ...
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WebFeb 1, 2016 · 2 Answers. Sorted by: 4. The 8086 calculates a 20-bit physical address by taking the SS register and shifting it left by 4. To this is added the SP offset. In your … WebJun 2, 2011 · 12. To really explain the concept, we have to back up to the basic idea of segments, and how the x86 uses them (in real mode). The 8086 has 20-bit addressing, but only 16-bit registers. To generate 20-bit addresses, it combines a segment with an offset. The segment has to be in a segment register (CS, DS, ES, or SS). greenfield ca optometry
Solved If CS=2000H, DS=4000H, SS=5000H, ES=8000H, …
WebAnswer to Solved If CS=2000H, DS=4000H, SS=5000H, ES=8000H, BX=1234H, This problem has been solved! You'll get a detailed solution from a subject matter expert that … WebThe pointer registers are 32-bit EIP, ESP, and EBP registers and corresponding 16-bit right portions IP, SP, and BP. There are three categories of pointer registers −. Instruction Pointer (IP) − The 16-bit IP register stores the offset address of the next instruction to be executed. IP in association with the CS register (as CS:IP) gives ... WebMOV CX, 1234h ; immediate nilai 16 bit bilangan heksa ... mode pengalamatan ini digunakan untuk merubah isi dari CS dan IP dengan Instruksi dari segment dan … greenfield capital oü